Homework problems? I'll help you out

I know there has been a thread about this, but it's long gone, so I decided to make a new one.

If anyone has problems concerning math, chemistry, biology, geography or history I'm here for you to try and solve or explain it to you.

EDIT
I'm doing this because I'm older than most of you guys so I might have more knowledge on some of these subjects and I've been in the same situation where I seriously needed some help.

 

Umg, what are your hours?
I might be needing math help
but can't be bothered with it now :p

 

idk I'll see when I'm on

 

halp meh.....

If you showed me the steps on how to solve this problem it would be greatly appreciated.

Find constants A and B that make the equation true

2x-9/x^2- x- 6 = A/x-3 + B/x+2
/ as in fraction and ^2 as squared

i don't understand it, do you find the least common denominator first?

 

I figured out what you were asking for so I deleted my last comment.



You have


(2x-9) / (x2-x-6) = [ A / (x-3) ] + [ B / (x+2) ]

I only used two types of brackets to establish a clear difference/separation between the two.


Basically, x2-x-6 is the same as (x-3)(x+2) since -3+2=-1 (given that the x term is the opposite of the sum of the two roots which in this case are 3 and -2, which add up to 1).


On the other side of the equation we have a denominator of x-3 and x+2. As you asked, there needs to be a common denominator to add the two parts on the right side.


As I said in the first paragraph, (x-3)(x+2)= x2-x-6, so we while we add [ A / (x-3) ] + [ B / (x+2) ] together, we can at the same time make the denominator equal to the denominator on the left side of the equation.


Remember whatever you do the the denominator, you must do to the numerator.


You basically multiply the A part to get


A(x+2)/ (x-3)(x+2)


Then the B part to get


B(x-3)/ (x-3)(x+2)


Now the denominators are the same so you can add the numerators (after you distribute the A(x+2) andB(x-3) ).


(Ax+2A + Bx-3B) / (x-3)(x+2)


(Ax+2A + Bx-3B) / x2-x-6



Now we have


(2x-9) / (x2-x-6) = (Ax+2A + Bx-3B) / (x2-x-6)


As a result of the same denominator, you know that the numerators on both sides will add up to be equal.



Numerator left = Numerator right

(2x-9) = (Ax+2A + Bx-3B)

2x-9= Ax+2A + Bx-3B


Now we get to the interesting part.


We have one equation and two variables. You may say it is impossible to solve it, but it is not.


We know Ax+2A + Bx-3B will equal 2x-9


We have two terms with x and two terms that don’t have x. So we can assume Ax + Bx will have to add up to the X term on the other side of the equation, since A and B are constants (will not have x in either of them). Due the reasoning in the last sentence, we can now assume 2A and -3B will have to add up to the term that doesn’t have a variable on the other side of the equation.


By these observations we get two equations with two variables.


Ax+Bx=2x —> A+B=2


2A-3B=-9


Now, we can easily solve for A and B. I’ll leave that to you.


A+B=2


2A-3B= -9

 

Seems about right!

 

How would you verify this trig identity?

(sin(x)cos(y) + sin(y)cos(x))/(cos(x)cos(y) - sin(x)sin(y))= (tan(x) + tan(y))/(1-tan(x)tan(y))

 

I take the right part of the equation:
(tan(x) + tan(y))/(1-tan(x)tan(y))

= (sinx/cosx + siny/cosy)/(1-((sinx/cosx)(siny/cosy))) formula: replace every tan with sin/cos

= [(sinycosy + sinycosx)/cosxcosy]/[(cosxcosy - sinxsiny)/cosxcosy]

= (sinxcosy + sinycosx)/(cosxcosy - sinxsiny) = left part of the equation

 

2+2, it's sooöôòøōóõ hard I need some long explanation for this, or I slap you

 

4 ._.

Count with your fingers.. 1 2 3 4
If you add the first 2 specific thing and another 2 specific thing, you got 4 specific things..

 

slap me

 

I don't have fingers ._.

*SLAP* Go to your Bedroom now Johnny this is unbelievable!

 

What does magicnerd + 808's number if

m = 1
a = 2
g = 3
i = 4
c = 5
n = 6
e = 69
r = 69
d = 1337?

@magicnerd808

Spoiler: The Answer

4583129040

 

Ummm
Realleh needz halp

1+1
.__.
I dun understandz

 

You guys think asking simple, stupid questions is funny. It is not. This thread was mainly created to help people in a serious way, so please stop fooling around to raise your post count or make a comment that you think will get many likes.

 

THANK YO SO MUCHEEEE :D

 

What the fuck is a pythagoreas

 

If I have Monday and Tuesday to edit and upload clips from our assembly and football game, and I have about 45 mins per day, each section of the video takes about two minutes, will I have enough time to finish it if I'm working with a partner?
Also, please explain Angle angle postulate for me? I still don't get it after numerous tutoring fails。

 

The AA postulate states that when you are given two triangles with two of the same angles. Due to a triangle having two angles given. you can easily find out the third angle, which means that both triangles will have the same third angle. Therefore, all the corresponding angles are equal on the two triangles. However, the triangles are only similar not equal since the lengths of the sides can be different. The dimensions of one triangle will have a ratio that compares its lengths to the lengths of the second triangle.